STUDENT SPACE · TOPIC 4
Concentration and titration calculations
Convert concentration units and calculate unknown concentration from titration data.
The essentials
- Use the final volume of the solution, not the volume of water added.
- n = cV; V = n/c. Use V in dm³ when c is in mol/dm³.
- Molar concentration: amount (mol) ÷ solution volume (dm³).
- Mass concentration: mass (g) ÷ solution volume (dm³).
Key vocabulary
| English | Chinese |
|---|
| concentration | 浓度 |
| solution volume | 溶液体积 |
| titration | 滴定 |
Quick practice
Try each question before opening its hint or answer. Use paper for calculations and diagrams.
Question 1
Why does the expression 0.100 × 20.0 give the wrong number of moles for 20.0 cm³ solution?
Need a hint for Question 1?
Use the relationships above and check particle ratios and units.
Check Question 1
The volume must be in dm³: use 0.0200, not 20.0.
Question 2
4.0 g NaOH is made up to 250 cm³ solution. Find concentration in g/dm³ and mol/dm³. M = 40 g/mol.
Need a hint for Question 2?
Convert 250 cm³ to dm³; use mass or moles per volume.
Check Question 2
4.0/0.250 = 16 g/dm³; (4.0/40)/0.250 = 0.40 mol/dm³.
Question 3
HCl + NaOH → NaCl + H₂O. Find the volume of 0.100 mol/dm³ NaOH needed for 25.0 cm³ of 0.200 mol/dm³ HCl.
Need a hint for Question 3?
Find acid moles, use the 1:1 ratio and then calculate alkali volume.
Check Question 3
n(HCl) = 0.200 × 0.0250 = 0.00500 mol. V(NaOH) = 0.0500 dm³ = 50.0 cm³.
Use Lesson 4 in your worksheet for written practice. Your teacher will discuss those answers in class.
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